Kakadu 16.01.2013 09:03

А кто-то там говорил, что камлёвые полиморфные варианты выдают длинные непонятные бесполезные сообщения об ошибках. А как вам это? Она думает, что я с 1го раза не пойму какой метод?

overloaded method value parseAll with alternatives: ([T(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll) (in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)](p: _663.Parser[T(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)], in: CharSequence)_663.ParseResult[T(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)]) forSome { val _663: kakadu.Arith }
<and>
([T(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)](p: _664.Parser[T(in method parseAll) (in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)], in: java.io.Reader)_664.ParseResult[T(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)(in method parseAll)]) forSome { val _664: kakadu.Arith }
<and>
([T](p: _665.Parser[T], in: scala.util.parsing.input.Reader[Char])_665.ParseResult[T]) forSome { val _665: kakadu.Arith } cannot be applied to (kakadu.Arith#Parser[Double], String)

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